Tìm x: a,1-√2x≥5 b, √x^4=√2.√5

Question

Tìm x:
a,1-√2x≥5
b, √x^4=√2.√5

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Nho 6 years 2020-11-07T04:55:47+00:00 2 Answers 90 views 0

Answers ( )

    0
    2020-11-07T04:57:18+00:00

    a) $1-\sqrt{2x}≥5$

    $↔\sqrt{2x}≥-4$

    $↔2x≥16$

    $↔x≥8$

    b) $\sqrt{x^4}=\sqrt{2}.\sqrt{5}$

    $↔x^2=\sqrt{10}$

    $↔\begin{cases}x=\sqrt[4]{10}\\x=-\sqrt[4]{10}\end{cases}$

     

    0
    2020-11-07T04:57:35+00:00

    a) `1-sqrt(2x) ≥5`

    `⇒sqrt(2x)≥-4`

    `⇒2x≥16`

    `⇒x≥8`

    b) `sqrt(x^4)=sqrt2 .sqrt5`

    `⇒x^2=sqrt10`

    $⇒x=±\sqrt[4]{10}$ 

     

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