Tìm x: a,1-√2x≥5 b, √x^4=√2.√5 Question Tìm x: a,1-√2x≥5 b, √x^4=√2.√5 in progress 0 Môn Toán Nho 6 years 2020-11-07T04:55:47+00:00 2020-11-07T04:55:47+00:00 2 Answers 90 views 0
Answers ( )
a) $1-\sqrt{2x}≥5$
$↔\sqrt{2x}≥-4$
$↔2x≥16$
$↔x≥8$
b) $\sqrt{x^4}=\sqrt{2}.\sqrt{5}$
$↔x^2=\sqrt{10}$
$↔\begin{cases}x=\sqrt[4]{10}\\x=-\sqrt[4]{10}\end{cases}$
a) `1-sqrt(2x) ≥5`
`⇒sqrt(2x)≥-4`
`⇒2x≥16`
`⇒x≥8`
b) `sqrt(x^4)=sqrt2 .sqrt5`
`⇒x^2=sqrt10`
$⇒x=±\sqrt[4]{10}$