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The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100
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The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100 mL of perchloric acid is neutralized by exactly 46.9 mL of 0.75 M lithium hydroxide. What is the concentration of the perchloric acid?
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Chemistry
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2021-09-04T05:44:31+00:00
2021-09-04T05:44:31+00:00 1 Answers
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Answer:
[HClO₄] = 0.35 M
Explanation:
Neutralization reaction is:
HClO₄ + LiOH → LiClO₄ + H₂O
In this case, we have a titration between a weak acid and a strong base.
In chemistry it is also called an acid base equilibrium.
HClO₄ + H₂O ⇄ ClO₄⁻ + H₃O⁺ Ka
The weak acid is firstly neutralized by the strong base, in order to have a buffer solution before the equivalence point.
When we reach the equivalence point, mmoles of acid = mmoles of base and there is a formula to determine it so:
M acid . Volume of acid = M base . Volume of base
M acid . 100 mL = 0.75 M . 46.9 mL
M acid = (0.75 M . 46.9 mL) / 100 mL → 0.35 M