The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100

Question

The reaction of perchloric acid (HClO4) with lithium hydroxide (LiOH) is described by the equation: HClO4 + LiOH → LiClO4 + H2O Suppose 100 mL of perchloric acid is neutralized by exactly 46.9 mL of 0.75 M lithium hydroxide. What is the concentration of the perchloric acid?

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Thu Hương 1 year 2021-09-04T05:44:31+00:00 1 Answers 22 views 0

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    2021-09-04T05:46:00+00:00

    Answer:

    [HClO₄] = 0.35 M

    Explanation:

    Neutralization reaction is:

    HClO₄ + LiOH  →  LiClO₄  +  H₂O

    In this case, we have a titration between a weak acid and a strong base.

    In chemistry it is also called an acid base equilibrium.

    HClO₄  +  H₂O  ⇄  ClO₄⁻   +  H₃O⁺       Ka

    The weak acid is firstly neutralized by the strong base, in order to have a buffer solution before the equivalence point.

    When we reach the equivalence point, mmoles of acid = mmoles of base and there is a formula to determine it so:

    M acid . Volume of acid = M base . Volume of base

    M acid . 100 mL = 0.75 M . 46.9 mL

    M acid = (0.75 M . 46.9 mL) / 100 mL → 0.35 M

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