Question

The average kinetic energy of the molecules of an ideal gas at 10∘C has the value K10. At what temperature T1 (in degrees Celsius) will the average kinetic energy of the same gas be twice this value, 2K10? Express the temperature to the nearest integer. View Available Hint(s) T1 T 1 T_1 = nothing ∘C Part B The molecules in an ideal gas at 10∘C have a root-mean-square (rms) speed vrms. At what temperature T2 (in degrees Celsius) will the molecules have twice the rms speed, 2vrms? Express the temperature to the nearest integer. View Available Hint(s) T2 T 2 T_2 = nothing ∘C




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