S8 +O2 = SO8 Given 80 mols of product, find the amount of each reactant in mols.

0 thoughts on “S8 +O2 = SO8 Given 80 mols of product, find the amount of each reactant in mols.”

1. Answer:

   10 moles of S₈

   320 moles O₂

   Explanation:

   • S₈ +O₂ → SO₈

   The balanced equation is:

   • S₈ + 32O₂ → 8SO₈

   Now we can convert moles of SO₈ (the product) into moles of each reactant, using the stoichiometric coefficients of the balanced reaction:

   • 80 mol SO₈ * [tex]\frac{1molS_8}{8molSO_8}[/tex] = 10 mol S₈

   • 80 mol SO₈ * [tex]\frac{32molO_2}{8molSO_8}[/tex] = 320 mol O₂

   In order for 80 moles of SO₈ to be produced, 10 moles of S₈ need to react with 320 moles of O₂.

   Reply