S8 +O2 = SO8 Given 80 mols of product, find the amount of each reactant in mols.

Question

S8 +O2 = SO8

Given 80 mols of product, find the amount of each reactant in mols.

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Thiên Thanh 5 months 2021-09-05T15:29:20+00:00 1 Answers 4 views 0

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    2021-09-05T15:31:16+00:00

    Answer:

    10 moles of S₈

    320 moles O₂

    Explanation:

    • S₈ +O₂ → SO₈

    The balanced equation is:

    • S₈ + 32O₂ → 8SO₈

    Now we can convert moles of SO₈ (the product) into moles of each reactant, using the stoichiometric coefficients of the balanced reaction:

    • 80 mol SO₈ * \frac{1molS_8}{8molSO_8} = 10 mol S₈
    • 80 mol SO₈ * \frac{32molO_2}{8molSO_8} = 320 mol O₂

    In order for 80 moles of SO₈ to be produced, 10 moles of S₈ need to react with 320 moles of O₂.

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