Which polynomial function has a root of 1 with multiplicity 2 and a root of 6 with multiplicity 1? Of(x) = (x – 1)(x – 6)

Question

Which polynomial function has a root of 1 with
multiplicity 2 and a root of 6 with multiplicity 1?
Of(x) = (x – 1)(x – 6)
O f(x) = 2(x – 1)(x – 6)
O f(x) = (x – 1)(x – 1)(x – 6)
O f(x) = (x – 1)(x – 6)(x-6)

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Kiệt Gia 3 years 2021-08-02T15:28:48+00:00 1 Answers 34 views 0

Answers ( )

  1. quangkhai
    0
    2021-08-02T15:30:03+00:00
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    Answer:

    The 3rd:

    f(x) = (x – 1)(x – 1)(x – 6)

    Step-by-step explanation:

    Its roots are the x-values for which f(x)=0, that are:

    x1=1

    x2=1

    x3=6

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )