Which polynomial function has a root of 1 with
multiplicity 2 and a root of 6 with multiplicity 1?
Of(x) = (x – 1)(x – 6)
O f(x) = 2(x – 1)(x – 6)
O f(x) = (x – 1)(x – 1)(x – 6)
O f(x) = (x – 1)(x – 6)(x-6)
Which polynomial function has a root of 1 with
multiplicity 2 and a root of 6 with multiplicity 1?
Of(x) = (x – 1)(x – 6)
O f(x) = 2(x – 1)(x – 6)
O f(x) = (x – 1)(x – 1)(x – 6)
O f(x) = (x – 1)(x – 6)(x-6)
Answer:
The 3rd:
f(x) = (x – 1)(x – 1)(x – 6)
Step-by-step explanation:
Its roots are the x-values for which f(x)=0, that are:
x1=1
x2=1
x3=6