Which polynomial function has a root of 1 with

multiplicity 2 and a root of 6 with multiplicity 1?

Of(x) = (x – 1)(x – 6)

O f(x) = 2(x – 1)(x – 6)

O f(x) = (x – 1)(x – 1)(x – 6)

O f(x) = (x – 1)(x – 6)(x-6)

multiplicity 2 and a root of 6 with multiplicity 1?

Of(x) = (x – 1)(x – 6)

O f(x) = 2(x – 1)(x – 6)

O f(x) = (x – 1)(x – 1)(x – 6)

O f(x) = (x – 1)(x – 6)(x-6)

Answer:The 3rd:

f(x) = (x – 1)(x – 1)(x – 6)

Step-by-step explanation:Its roots are the x-values for which f(x)=0, that are:

x1=1

x2=1

x3=6