What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form

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What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form

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Calantha 3 years 2021-09-02T00:40:51+00:00 1 Answers 0 views 0

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    2021-09-02T00:41:51+00:00

    Answer:

    y=-5x+4

    Step-by-step explanation:

    m=(y2-y1)/(x2-x1)

    m=(-16-(-6))/(4-2)

    m=(-16+6)/2

    m=-10/2

    m=-5

    y-y1=m(x-x1)

    y-(-6)=-5(x-2)

    y+6=-5(x-2)

    y+6=-5x+10

    y=-5x+10-6

    y=-5x+4

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )