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What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form
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What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form
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Mathematics
3 years
2021-09-02T00:40:51+00:00
2021-09-02T00:40:51+00:00 1 Answers
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Answer:
y=-5x+4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-16-(-6))/(4-2)
m=(-16+6)/2
m=-10/2
m=-5
y-y1=m(x-x1)
y-(-6)=-5(x-2)
y+6=-5(x-2)
y+6=-5x+10
y=-5x+10-6
y=-5x+4