Question What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form

Answer: y=-5x+4 Step-by-step explanation: m=(y2-y1)/(x2-x1) m=(-16-(-6))/(4-2) m=(-16+6)/2 m=-10/2 m=-5 y-y1=m(x-x1) y-(-6)=-5(x-2) y+6=-5(x-2) y+6=-5x+10 y=-5x+10-6 y=-5x+4 Log in to Reply

Answer:y=-5x+4

Step-by-step explanation:m=(y2-y1)/(x2-x1)

m=(-16-(-6))/(4-2)

m=(-16+6)/2

m=-10/2

m=-5

y-y1=m(x-x1)

y-(-6)=-5(x-2)

y+6=-5(x-2)

y+6=-5x+10

y=-5x+10-6

y=-5x+4