Question What is the equation of a line passing through the points (2, -6) and (4, -16) in slope-intercept form
Answer: y=-5x+4 Step-by-step explanation: m=(y2-y1)/(x2-x1) m=(-16-(-6))/(4-2) m=(-16+6)/2 m=-10/2 m=-5 y-y1=m(x-x1) y-(-6)=-5(x-2) y+6=-5(x-2) y+6=-5x+10 y=-5x+10-6 y=-5x+4 Log in to Reply
Answer:
y=-5x+4
Step-by-step explanation:
m=(y2-y1)/(x2-x1)
m=(-16-(-6))/(4-2)
m=(-16+6)/2
m=-10/2
m=-5
y-y1=m(x-x1)
y-(-6)=-5(x-2)
y+6=-5(x-2)
y+6=-5x+10
y=-5x+10-6
y=-5x+4