The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.8° wh

Question

The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.8° what is the index of refraction of the material?

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Yến Oanh 3 years 2021-07-30T08:34:37+00:00 1 Answers 20 views 0

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    2021-07-30T08:35:41+00:00

    Answer:

    the index of refraction of the material is 1.53

    Explanation:

    c=40.8 degree

    c = sin⁻¹ (n2/n1)

    n2=1

    then

    For total internal reflection

    sin40.8 = 1 / n1

    0.6534 = 1 / n1

    n1 = 1 / 0.6534

    n1 = 1.53

    Thus, the index of refraction of the material is 1.53

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