The refractive index of a transparent material can be determined by measuring the critical angle when the solid is in air. If θc= 40.8° what is the index of refraction of the material?
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Answer:
the index of refraction of the material is 1.53
Explanation:
c=40.8 degree
c = sin⁻¹ (n2/n1)
n2=1
then
For total internal reflection
sin40.8 = 1 / n1
0.6534 = 1 / n1
n1 = 1 / 0.6534
n1 = 1.53
Thus, the index of refraction of the material is 1.53