Question 5 An instrument plays a frequency of 266 Hz. Another identical instrument plays a frequency of 400 Hz. How do the wavelength

Question

Question 5
An instrument plays a frequency of 266 Hz. Another identical instrument plays a frequency of 400 Hz. How do the wavelength of each of these
sound waves compare?

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Thu Nguyệt 2 months 2021-07-25T22:03:15+00:00 1 Answers 2 views 0

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    2021-07-25T22:04:18+00:00

    Answer:

    the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

    Explanation:

    Given:

    f₁ = frequency = 266 Hz

    f₂ = 400 Hz

    Question: How do the wavelength of each of these sound waves compare, λ₁ = ?, λ₂ = ?

    The equation to solve this question is

    \lambda =\frac{v}{f}

    Here

    λ = wavelength of the sound

    v = speed of sound = 340 m/s

    f = frequency of each instrument

    You need to calculate both wavelengths

    \lambda _{1} =\frac{v}{f_{1} } =\frac{340}{266} =1.2782m

    \lambda _{2} =\frac{v}{f_{2} } =\frac{340}{400} =0.85m

    Ratio=\frac{\lambda _{1}}{\lambda _{2} } =\frac{1.2782}{0.85} =1.5038

    According to the results, the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

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