Question 5 An instrument plays a frequency of 266 Hz. Another identical instrument plays a frequency of 400 Hz. How do the wavelength

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Question 5
An instrument plays a frequency of 266 Hz. Another identical instrument plays a frequency of 400 Hz. How do the wavelength of each of these
sound waves compare?

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  1. Answer:

    the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

    Explanation:

    Given:

    f₁ = frequency = 266 Hz

    f₂ = 400 Hz

    Question: How do the wavelength of each of these sound waves compare, λ₁ = ?, λ₂ = ?

    The equation to solve this question is

    [tex]\lambda =\frac{v}{f}[/tex]

    Here

    λ = wavelength of the sound

    v = speed of sound = 340 m/s

    f = frequency of each instrument

    You need to calculate both wavelengths

    [tex]\lambda _{1} =\frac{v}{f_{1} } =\frac{340}{266} =1.2782m[/tex]

    [tex]\lambda _{2} =\frac{v}{f_{2} } =\frac{340}{400} =0.85m[/tex]

    [tex]Ratio=\frac{\lambda _{1}}{\lambda _{2} } =\frac{1.2782}{0.85} =1.5038[/tex]

    According to the results, the wavelength of the first instrument is approximately 1.5 greater than that produced by the second instrument.

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