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If a person can comfortably carry 20 kg (44 lbs) and gold has a density of 19.6 g/cm3, what is the volume of the largest piece of solid gold
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Answers ( )
Answer:
1.02×10⁻³ m³
Explanation:
Density = mass/volume.
D = m/V…………………equation 1
Make V the subject of the equation
V = m/D……………….. Equation 2
Where V = Volume of the largest piece of solid gold a person can carry, D = Density of the Gold, m = mass a person can comfortably carry.
Given: m = 20 kg, D = 19.6 g/cm³ = 19.6(1000000/1000) kg/m³ = 19600 kg/m³
Substitute into equation 2
V = 20/19600
V = 1.02×10⁻³ m³
Hence the volume of the largest piece of solid gold a person can carry = 1.02×10⁻³ m³