If a person can comfortably carry 20 kg (44 lbs) and gold has a density of 19.6 g/cm3, what is the volume of the largest piece of solid gold a person can carry

Answers

Answer:

1.02×10⁻³ m³

Explanation:

Density = mass/volume.

D = m/V…………………equation 1

Make V the subject of the equation

V = m/D……………….. Equation 2

Where V = Volume of the largest piece of solid gold a person can carry, D = Density of the Gold, m = mass a person can comfortably carry.

Given: m = 20 kg, D = 19.6 g/cm³ = 19.6(1000000/1000) kg/m³ = 19600 kg/m³

Substitute into equation 2

V = 20/19600

V = 1.02×10⁻³ m³

Hence the volume of the largest piece of solid gold a person can carry = 1.02×10⁻³ m³

Answer:1.02×10⁻³ m³Explanation:Density = mass/volume.

D = m/V…………………equation 1

Make V the subject of the equation

V = m/D……………….. Equation 2

Where V = Volume of the largest piece of solid gold a person can carry, D = Density of the Gold, m = mass a person can comfortably carry.

Given: m = 20 kg, D = 19.6 g/cm³ = 19.6(1000000/1000) kg/m³ = 19600 kg/m³

Substitute into equation 2

V = 20/19600

V = 1.02×10⁻³ m³

Hence the volume of the largest piece of solid gold a person can carry = 1.02×10⁻³ m³