If a is a non-zero constant, determine the vertex of y = -3(x + a)^2 – 6

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If a is a non-zero constant, determine the vertex of y = -3(x + a)^2 – 6

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Orla Orla 3 years 2021-08-14T16:10:41+00:00 1 Answers 9 views 0

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    2021-08-14T16:11:51+00:00

    Answer:

    Vertex is (-a, -6), where a ≠ 0.

    General Formulas and Concepts:

    Algebra I

    • Coordinates (x, y)
    • Quadratics

    Algebra II

    Vertex Form: y = a(bx – h)² + k

    • a is the vertical scale factor
    • b is the horizontal scale factor
    • (h, k) is the vertex

    Step-by-step explanation:

    Step 1: Define

    y = -3(x + a)² – 6

    Identify variables

    a = -3

    b = 1

    (h, k) = (-a, -6)

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )