If a is a non-zero constant, determine the vertex of y = -3(x + a)^2 – 6
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Question
If a is a non-zero constant, determine the vertex of y = -3(x + a)^2 – 6
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Answer:
Vertex is (-a, -6), where a ≠ 0.
General Formulas and Concepts:
Algebra I
Algebra II
Vertex Form: y = a(bx – h)² + k
Step-by-step explanation:
Step 1: Define
y = -3(x + a)² – 6
↓ Identify variables
a = -3
b = 1
(h, k) = (-a, -6)