Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3 internally and externally

Question

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3
internally and externally

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Kiệt Gia 1 year 2021-09-04T05:12:30+00:00 1 Answers 102 views 0

Answers ( )

    0
    2021-09-04T05:13:48+00:00

    Answer:

    Known two points, list function expression, use

    [tex]y-y_{0}=k(x-x_{0})[/tex]

    [tex]k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }[/tex]

    The function expression is

    [tex]y=\frac{4}{7}x-3[/tex]

    It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = – 7 / 5.

    So the result is   [tex](\frac{14}{5} ,-\frac{7}{5} )[/tex]

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )