# Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3 internally and externally

Question

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3
internally and externally

in progress 0
1 year 2021-09-04T05:12:30+00:00 1 Answers 102 views 0

Known two points, list function expression, use

$$y-y_{0}=k(x-x_{0})$$

$$k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }$$

The function expression is

$$y=\frac{4}{7}x-3$$

It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = – 7 / 5.

So the result is   $$(\frac{14}{5} ,-\frac{7}{5} )$$