Question

Find the points which divide the line segment joining the points (0, -3) and (7,1) in the ratio 2:3
internally and externally

Answers

  1. Answer:

    Known two points, list function expression, use

    y-y_{0}=k(x-x_{0})

    k= \frac{y_{2} -y_{1\\}}{x_{2} -x_{1} }

    The function expression is

    y=\frac{4}{7}x-3

    It is known that the cross section of two points is 7, so the point of 2:3 is 14 / 5, that is, 0 + 14 / 5 is the abscissa of the point, which is substituted into the original equation to get y = – 7 / 5.

    So the result is   (\frac{14}{5} ,-\frac{7}{5} )

Leave a Comment