Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly for lunch. If the lily pads are spaced 2.4 m apart, an

Question

Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly
for lunch. If the lily pads are spaced 2.4 m apart, and Ferdinand jumps with a
speed of 5.4m/s, taking 0.60 s to go from lily pad to lily pad, at what angle
must Ferdinand make each of his jumps?

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Delwyn 2 months 2021-07-30T03:21:05+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-07-30T03:22:26+00:00

    Answer:

    θ = 33°

    Explanation:

    Here, we can use the formula for the total time of flight of a projectile to calculate the launch angle of frog:

    T = \frac{2\ u\ Sin\theta}{g} \\\\Sin\theta = \frac{Tg}{2u}

    where,

    θ = launch angle = ?

    T = Total time of flight = 0.6 s

    g = acceleration due to gravity = 9.81 m/s²

    u = launch speed = 5.4 m/s

    Therefore,

    Sin\theta = \frac{(0.6\ s)(9.81\ m/s^2)}{(2)(5.4\ m/s)}\\\\\theta = Sin^{-1}(0.545)

    θ = 33°

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