Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly for lunch. If the lily pads are spaced 2.4 m apart, an

Question

Ferdinand the frog is hopping from lily pad to lily pad in search of a good fly
for lunch. If the lily pads are spaced 2.4 m apart, and Ferdinand jumps with a
speed of 5.4m/s, taking 0.60 s to go from lily pad to lily pad, at what angle
must Ferdinand make each of his jumps?

in progress 0
Delwyn 5 years 2021-07-30T03:21:05+00:00 1 Answers 169 views 0

Answers ( )

  1. Nem
    0
    2021-07-30T03:22:26+00:00
    Reply

    Answer:

    θ = 33°

    Explanation:

    Here, we can use the formula for the total time of flight of a projectile to calculate the launch angle of frog:

    T = \frac{2\ u\ Sin\theta}{g} \\\\Sin\theta = \frac{Tg}{2u}

    where,

    θ = launch angle = ?

    T = Total time of flight = 0.6 s

    g = acceleration due to gravity = 9.81 m/s²

    u = launch speed = 5.4 m/s

    Therefore,

    Sin\theta = \frac{(0.6\ s)(9.81\ m/s^2)}{(2)(5.4\ m/s)}\\\\\theta = Sin^{-1}(0.545)

    θ = 33°

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )