Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16] What is the percentage oxygen in N2O5? (Give your answer in 4 signif

Question

Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]
What is the percentage oxygen in N2O5? (Give your answer in 4 significant figures)​

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Thiên Di 2 weeks 2021-09-05T12:27:58+00:00 1 Answers 0 views 0

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    2021-09-05T12:29:00+00:00

    Answer:

    74.08%

    Explanation:

    We’ll begin by calculating the mass of

    Oxygen in 4 g of N₂O₅. This can be obtained as follow:

    Molar mass of N₂O₅ = (14×2) + (16×5)

    = 28 + 80

    = 108 g/mol

    Mass of oxygen in N₂O₅ = 5 × 16 = 80 g

    Mass of oxygen in 4 g of N₂O₅

    = 80 / 108 × 4

    = 2.963 g

    Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow:

    Mass of oxygen = 2.963 g

    Mass of N₂O₅ = 4 g

    Percentage of oxygen =?

    Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100

    Percentage of oxygen = 2.963 / 4 × 100

    Percentage of oxygen = 74.08%

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