Question Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]What is the percentage oxygen in N2O5? (Give your answer in 4 significant figures)

Answer: 74.08% Explanation: We’ll begin by calculating the mass of Oxygen in 4 g of N₂O₅. This can be obtained as follow: Molar mass of N₂O₅ = (14×2) + (16×5) = 28 + 80 = 108 g/mol Mass of oxygen in N₂O₅ = 5 × 16 = 80 g Mass of oxygen in 4 g of N₂O₅ = 80 / 108 × 4 = 2.963 g Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow: Mass of oxygen = 2.963 g Mass of N₂O₅ = 4 g Percentage of oxygen =? Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100 Percentage of oxygen = 2.963 / 4 × 100 Percentage of oxygen = 74.08% Log in to Reply

Answer:

74.08%

Explanation:

We’ll begin by calculating the mass of

Oxygen in 4 g of N₂O₅. This can be obtained as follow:

Molar mass of N₂O₅ = (14×2) + (16×5)

= 28 + 80

= 108 g/mol

Mass of oxygen in N₂O₅ = 5 × 16 = 80 g

Mass of oxygen in 4 g of N₂O₅

= 80 / 108 × 4

= 2.963 g

Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow:

Mass of oxygen = 2.963 g

Mass of N₂O₅ = 4 g

Percentage of oxygen =?

Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100

Percentage of oxygen = 2.963 / 4 × 100

Percentage of oxygen = 74.08%