Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]
What is the percentage oxygen in N2O5? (Give your answer in 4 significant figures)
Question
Question
Consider 4 g N2O5, in a test tube. [Given: Ar(N) = 14, Ar(O) = 16]
What is the percentage oxygen in N2O5? (Give your answer in 4 significant figures)
Answer:
74.08%
Explanation:
We’ll begin by calculating the mass of
Oxygen in 4 g of N₂O₅. This can be obtained as follow:
Molar mass of N₂O₅ = (14×2) + (16×5)
= 28 + 80
= 108 g/mol
Mass of oxygen in N₂O₅ = 5 × 16 = 80 g
Mass of oxygen in 4 g of N₂O₅
= 80 / 108 × 4
= 2.963 g
Finally, we shall determine the percentage of oxygen in 4 g of N₂O₅. This can be obtained as follow:
Mass of oxygen = 2.963 g
Mass of N₂O₅ = 4 g
Percentage of oxygen =?
Percentage of oxygen = mass of oxygen / mass of N₂O₅ × 100
Percentage of oxygen = 2.963 / 4 × 100
Percentage of oxygen = 74.08%