An object launched straight puwar from the ground level wiht an initional velocity of 32 feet per second.The formula H=32T-16T^2 gives it he

Question

An object launched straight puwar from the ground level wiht an initional velocity of 32 feet per second.The formula H=32T-16T^2 gives it heigtht,h,in feet after t second. At what time does the object hit the ground?

in progress 0
Vodka 3 weeks 2021-08-26T05:34:59+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-08-26T05:36:10+00:00

    Answer:

    2 secs after

    Step-by-step explanation:

    Given the height of the object modeled by the eqaution;

    H(t) = 32T – 16T² where;

    T is the time in seconds

    The object hits the ground when h(t)= 0

    Substitute H = 0 into the equation and get t as shown;

    0 =  32T – 16T²

    0-32T = -16T²

    -32T = -16T²

    32T = 16T²

    32 = 16T

    T = 32/16

    T = 2secs

    Hence the object hits the ground after 2 secs

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )