An object launched straight puwar from the ground level wiht an initional velocity of 32 feet per second.The formula H=32T-16T^2 gives it heigtht,h,in feet after t second. At what time does the object hit the ground?

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Answer:2 secs afterStep-by-step explanation:Given the height of the object modeled by the eqaution;

H(t) = 32T – 16T² where;

T is the time in seconds

The object hits the ground when h(t)= 0

Substitute H = 0 into the equation and get t as shown;

0 = 32T – 16T²

0-32T = -16T²

-32T = -16T²

32T = 16T²

32 = 16T

T = 32/16

T = 2secsHence the object hits the ground after 2 secs