An object is constrained by a cord to move in a circular path of radius 0.5 m on a horizontal frictionless surface. The cord will break if i

Question

An object is constrained by a cord to move in a circular path of radius 0.5 m on a horizontal frictionless surface. The cord will break if its tension exceeds 16 N. The maximum kinetic energy the object can have is:

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Ngọc Diệp 3 years 2021-08-26T09:23:20+00:00 1 Answers 12 views 0

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    2021-08-26T09:24:44+00:00

    Answer:

    4J

    Explanation:

    Centripetal Force = mv^2/r

    The radius is 0.5, so CF= 2mv^2

    2mv^2 = 16N

    mv^2 = 8

    Kinetic Energy = 1/2mv^2

    KE = 1/2(8)

    KE = 4J

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