An object is constrained by a cord to move in a circular path of radius 0.5 m on a horizontal frictionless surface. The cord will break if its tension exceeds 16 N. The maximum kinetic energy the object can have is:
An object is constrained by a cord to move in a circular path of radius 0.5 m on a horizontal frictionless surface. The cord will break if its tension exceeds 16 N. The maximum kinetic energy the object can have is:
Answer:
4J
Explanation:
Centripetal Force = mv^2/r
The radius is 0.5, so CF= 2mv^2
2mv^2 = 16N
mv^2 = 8
Kinetic Energy = 1/2mv^2
KE = 1/2(8)
KE = 4J