Question An object is constrained by a cord to move in a circular path of radius 0.5 m on a horizontal frictionless surface. The cord will break if its tension exceeds 16 N. The maximum kinetic energy the object can have is:

Answer: 4J Explanation: Centripetal Force = mv^2/r The radius is 0.5, so CF= 2mv^2 2mv^2 = 16N mv^2 = 8 Kinetic Energy = 1/2mv^2 KE = 1/2(8) KE = 4J Log in to Reply

Answer:

4J

Explanation:

Centripetal Force = mv^2/r

The radius is 0.5, so CF= 2mv^2

2mv^2 = 16N

mv^2 = 8

Kinetic Energy = 1/2mv^2

KE = 1/2(8)

KE = 4J