A golf ball is struck with a five iron on level ground. It lands 92.2 m away 4.30 s later. What were (a) the direction and (b) the magnitude

Question

A golf ball is struck with a five iron on level ground. It lands 92.2 m away 4.30 s later. What were (a) the direction and (b) the magnitude of the initial velocity

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Diễm Thu 1 week 2021-09-05T17:02:12+00:00 1 Answers 4 views 0

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    2021-09-05T17:04:03+00:00

    Answer:

    Vi = 29.83 m/s,   θ = 54.7⁰

    Explanation:

    Given:

    Horizontal Distance x= 92.2 m

    Time t = 4.30s s

    To find Initial Velocity Vi =?

    we have x = V t

    Vix= Horizontal Component and Viy is vertical Component

    Vix = x / t = 92.2 m / 4.30 s = 21.11 m/s

    from 2nd Eqn of motion

    y = Viy t + 1/2 g t²    

    0 = Viy × 4.3 + 0.5 × (-9.81) m/s² × (4.3)²

    we get Vy = 21.09 m/s

    Vi = Square root ( Vix ² + Viy²)

    Vi = 29.83 m/s

    For Direction

    Tan θ = Viy / vix

    ⇒  θ = Tan ⁻¹ ( 29.83  / 21.11 )

    θ = 54.7⁰

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