A golf ball is struck with a five iron on level ground. It lands 92.2 m away 4.30 s later. What were (a) the direction and (b) the magnitude of the initial velocity
Question
Question
A golf ball is struck with a five iron on level ground. It lands 92.2 m away 4.30 s later. What were (a) the direction and (b) the magnitude of the initial velocity
Answer:
Vi = 29.83 m/s, θ = 54.7⁰
Explanation:
Given:
Horizontal Distance x= 92.2 m
Time t = 4.30s s
To find Initial Velocity Vi =?
we have x = V t
Vix= Horizontal Component and Viy is vertical Component
Vix = x / t = 92.2 m / 4.30 s = 21.11 m/s
from 2nd Eqn of motion
y = Viy t + 1/2 g t²
0 = Viy × 4.3 + 0.5 × (-9.81) m/s² × (4.3)²
we get Vy = 21.09 m/s
Vi = Square root ( Vix ² + Viy²)
Vi = 29.83 m/s
For Direction
Tan θ = Viy / vix
⇒ θ = Tan ⁻¹ ( 29.83 / 21.11 )
θ = 54.7⁰