A ball is thrown from an initial height of 2 feet with an initial upward velocity of 21 fts. The ball’s height h (in feet) after seco

Question

A ball is thrown from an initial height of 2 feet with an initial upward velocity of 21 fts. The ball’s height h (in feet) after seconds is given by the following.

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Xavia 3 years 2021-09-05T03:01:33+00:00 1 Answers 6 views 0

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    2021-09-05T03:02:58+00:00

    Answer:

    h(t)=

    h(t)=vt-21t+2

    Step-by-step explanation:

    initial height =2

    initial velocity=21ft/s

    dh/dt=v

    dh=vdt

    intergrating both sides

    h(t)-h(i)=vt-v(i)t

    h(t)-2=vt-21t

    h(t)=vt-21t+2

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