A ball is thrown from an initial height of 2 feet with an initial upward velocity of 21 fts. The ball’s height h (in feet) after seconds is given by the following.
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A ball is thrown from an initial height of 2 feet with an initial upward velocity of 21 fts. The ball’s height h (in feet) after seconds is given by the following.
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Answer:
h(t)=
h(t)=vt-21t+2
Step-by-step explanation:
initial height =2
initial velocity=21ft/s
dh/dt=v
dh=vdt
intergrating both sides
h(t)-h(i)=vt-v(i)t
h(t)-2=vt-21t
h(t)=vt-21t+2