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A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag
Question
A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag so that the probability of randomly joined a blue marble is 1/3?
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Mathematics
5 years
2021-07-18T09:44:34+00:00
2021-07-18T09:44:34+00:00 1 Answers
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Answer:
5 blue marbles
Step-by-step explanation:
31/3 = about 10
15-10=5