A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag

Question

A bag contains 15 blue marbles, five red marbles, and 11 green marbles. How many blue marbles must be removed from the 31 marbles in the bag so that the probability of randomly joined a blue marble is 1/3?

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Delwyn 5 years 2021-07-18T09:44:34+00:00 1 Answers 13 views 0

Answers ( )

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    2021-07-18T09:45:42+00:00

    Answer:

    5 blue marbles

    Step-by-step explanation:

    31/3 = about 10

    15-10=5

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