Zeke’s car had an initial velocity os 12 m/sec slows down to 2 m/sec in 4.5 seconds. What is the acceleration of Zeke’s car? *

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Physics Thu Hương 5 years 2021-07-30T08:02:13+00:00 2021-07-30T08:02:13+00:00 1 Answers 20 views 0

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Captcha* Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )

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thongdat2 · Answer 1 · 2021-07-30T08:03:46+00:00

Answer:

$a=-2.22m/s^2$

Explanation:

the information we have is:

initial velocity: $v_{i}=12m/s$

final velocity: $v_{f}=2m/s$

and the time: $t=4.5s$

We need to find the acceleration of the car.

For this we use formula to calculate the acceleration given the information we were given:

$a=\frac{v_{f}-v_{i}}{t}$

acceleration is equal to the difference between the final velocity and the initial velocity divided by time.

We substitute all the known values:

$a=\frac{2m/s-12m/s}{4.5s}\\ \\a=\frac{-10m/s}{4.5s}\\ \\a=-2.22m/s^2$

the acceleration is $-2.22m/s^2$

the result is negative because the car is slowing down.