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You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference between the plates
Question
You slide a slab of dielectric between the plates of a parallel-plate capacitor. As you do this, the potential difference between the plates remains constant. What effect does adding the dielectric have on the energy stored in the capacitor?
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Physics
3 years
2021-09-05T04:06:59+00:00
2021-09-05T04:06:59+00:00 1 Answers
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Answer:
The energy stored by the capacitor is increased when a dielectric is added, with voltage or potential difference staying the same.
Explanation:
The capacitance of a parallel-plate capacitor will increase as a dielectric is added between the plates. This is according to the following equation for capacitance:
Here, C is the capacitance, E is the dielectric constant, A is the area, and d is the distance between the plates.
Since the value of E is 1 or higher, the capacitance will increase once the dielectric is added.
The energy of a capacitor is found from the following equation:
Energy =![Rendered by QuickLaTeX.com \frac{1}{2}CV^2](https://documen.tv/wp-content/ql-cache/quicklatex.com-716e568d602106977650e6f38e9e52f9_l3.png)
here C is the capacitance, and V is the voltage.
Since the voltage stays constant, while the capacitance increases in the energy equation, the overall energy stored by the capacitor also increases.