You illuminate a slit with a width of 77.7 μm with a light of wavelength 721 nm and observe the resulting diffraction pattern on a screen that is situated 2.83 m from the slit. What is the width, in centimeters, of the pattern’s central maximum

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Answer:The width is

Explanation:From the question we are told that

The width of the slit is

The wavelength of the light is

The position of the screen is

Generally angle at which the first minimum of the interference pattern the light occurs is mathematically represented as

Where m which is the order of the interference is 1

substituting values

Now the width of first minimum of the interference pattern is mathematically evaluated as

substituting values

Now the width of the pattern’s central maximum is mathematically evaluated as

substituting values