You are holding a 1 kg rock and standing at the top of a cliff. You drop the rock off the cliff and it falls a distance 10 m. In this problem, you can ignore air resistance.
What is the change in the kinetic energy of the rock as it falls that distance?
Question
Answer:
98J
Explanation:
Given that the mass of the rock m=1kg, the height =10m and we know that gravitational force is [tex]g=9.8N/kg[/tex].
Change in kinetic energy happens when the initial potential energy at rest is converted into Kinetic energy as:
[tex]\bigtriangleup KE=\bigtriangleup mgh\\\\=1kg\times 9.8\times10m\\\\=98J[/tex]
Hence, the change in kinetic energy of the rock is 98J