write the equation of a parellel to the given line that goes through the given point y=8x+3 (2,4)

Question

write the equation of a parellel to the given line that goes through the given point y=8x+3 (2,4)

in progress 0
Kim Cúc 3 years 2021-08-27T05:48:12+00:00 1 Answers 5 views 0

Answers ( )

    0
    2021-08-27T05:49:38+00:00

    Answer:

    The equation of a parallel to the given line that goes through the given point (2, 4) is:

    y=8x-12

    Step-by-step explanation:

    Given the equation

    y=8x+3

    comparing the equation with the slope-intercept form

    y=mx+b

    Here,

    • m is the slope
    • y is the intercept

    so the slope of the line is m = 8.

    We know that the slopes of parallel lines are equal.

    so, the slope of the perpendicular line will be = 8

    Therefore, the equation of a parallel to the given line that goes through the given point (2, 4) is:

    y-y_1=m\left(x-x_1\right)

    y-4 = 8 (x-2)

    y-4 = 8x-16

    y = 8x-16+4

    y=8x-12

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )