Question

what is the position of the car at the end of the 10 secs?

Answers

  1. Answer:

    S=400m

    Explanation:

    Given t=10.and a=8m/s^2,

    Initial velocity,u, of the car is zero.

    To find distance,s

    S=ut+0.5at^2

    S=0\times10+0.5\times8\times10^2\\S=400m

    Therefore, car’s position after 10seconds is 400m away from the start.

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