what is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4, 6)

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what is an equation of the line that is perpendicular to y + 1 = -3(x-5) and passes through the point (4, 6)

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Tài Đức 5 years 2021-08-25T08:51:02+00:00 1 Answers 20 views 0

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  1. Cherry
    0
    2021-08-25T08:52:17+00:00
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    Answer:

    y – 4 = 1/3(x-6)

    Step-by-step explanation:

    y-y₁=m(x-x₁)                 point slope formula

    Substitute in the 4 and 6 for the x_{1} and y_{1}

    Take the original slope of – 3 and change its sign and turn it into it’s reciprocal

    1/3

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