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“water is circulating in pipes in a two floor house. on the first floor the pressure is 340 kpa and the speed 2.8 m/s. the second floor is 4
Question
“water is circulating in pipes in a two floor house. on the first floor the pressure is 340 kpa and the speed 2.8 m/s. the second floor is 4m higher. calculate the pressure on the second floor of the areas are A1 1m2 and A2 2m2”
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Physics
5 years
2021-08-12T03:56:11+00:00
2021-08-12T03:56:11+00:00 1 Answers
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Answer:
Explanation:
We shall apply Bernoulli’s equation of flow of liquid
1 / 2 ρ v² + ρ gh + P = constant
For calculating velocity in second floor
A₁ V₁ = A₂ V₂
1 x 2.8 = 2 x V₂
V₂ = 1.4 m /s
1 / 2 ρ v₁² + ρ gh₁ + P₁ = 1 / 2 ρ v₂² + ρ gh₂ + P₂
.5 x 10³ x 2.8² + 10³ x 9.8h₁ + 340 x 10³ = .5 x 10³ x 1.4² + 10³ x 9.8 x h₂ + P₂
P₂ = 3.92 x 10³ + 9.8 x 10³ ( h₁ – h₂ ) + 340 x 10³ – .98 x 10³
= 3.92 x 10³ – 9.8 x 10³ x 4 + 340 x 10³ – .98 x 10³
= 303.74 x 10³ Pa
= 303.74 kPa .