Question Two speakers create identical 240 Hz sound waves. A person is 1.47 m from Speaker 1. What is the MINIMUM distance to Speaker 2 for there to be destructive interference at that spot? (Hint: v= lambda f=343 m/s) (Unit = m)

Answer: 2.90 metres Explanation: Distance of speaker 2 =? Distance of speaker 1 = 1.47m Velocity = 343 f = 240Hz For constructive interference to occur: Difference in distance or path = wavelength For minimum distance, n = 1 Distance 2 – distance 1 = nλ Recall λ = v/f V = Velocity ; f = frequency Distance 2 – distance 1 = v/f Distance 2 – 1.47 = (343/240) Distance 2 = 1.429 + 1.47 Distance 2 = 2.899 meters Minimum Distance of speaker 2 for their to be constructive interference = 2.90meters Log in to Reply

Answer:

0.755

Explanation:

Answer: 2.90 metres

Explanation:

Distance of speaker 2 =?

Distance of speaker 1 = 1.47m

Velocity = 343

f = 240Hz

For constructive interference to occur:

Difference in distance or path = wavelength

For minimum distance, n = 1

Distance 2 – distance 1 = nλ

Recall λ = v/f

V = Velocity ; f = frequency

Distance 2 – distance 1 = v/f

Distance 2 – 1.47 = (343/240)

Distance 2 = 1.429 + 1.47

Distance 2 = 2.899 meters

Minimum Distance of speaker 2 for their to be constructive interference = 2.90meters