Two positively charged particles are separated on an axis by 0.1 meters, and q1 has a 6 µC charge and q2 has a 2 µC charge. Recall that k =

Question

Two positively charged particles are separated on an axis by 0.1 meters, and q1 has a 6 µC charge and q2 has a 2 µC charge. Recall that k = 8.99 × 109 N • meters squared over Coulombs squared.. What is the force applied between q1 and q2 in N? In which direction does particle q2 want to go?

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Hưng Khoa 5 years 2021-08-19T05:08:34+00:00 2 Answers 470 views 0

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  1. ThanhThu
    0
    2021-08-19T05:10:01+00:00
    Reply

    Answer:

    10.8 N & away from particle q1, in a straight line to the right

    Explanation:

    •°•°•°

  2. Eirian
    0
    2021-08-19T05:10:01+00:00
    Reply

    Answer:

    Force between two charges is 10.8 N

    both charges are positive nature charge so they both repel each other and hence q2 will move away from charge q1

    Explanation:

    As we know that the force between two charge particles is given by Coulomb’s law of electrostatics

    So we will say it as

    F = \frac{kq_1q_2}{r^2}

    here we know that

    q_1 = 6\mu C

    q_2 = 2\mu C

    d = 0.1 m

    F = \frac{8.99 \times 10^9(6 \mu C)(2\mu C)}{0.1^2}

    F = 10.8 N

    Since both charges are positive nature charge so they both repel each other and hence q2 will move away from charge q1

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