Two blocks, joined by a string, have masses of 6.0 kg and 9.0 kg. They rest on a frictionless horizontal surface. A 2nd string, attached onl

Question

Two blocks, joined by a string, have masses of 6.0 kg and 9.0 kg. They rest on a frictionless horizontal surface. A 2nd string, attached only to the 9 kg block, has horizontal force = 30 N applied to it. Both blocks accelerate. Find the tension in the string between the blocks.

in progress 0
RobertKer 3 years 2021-09-04T11:38:05+00:00 1 Answers 227 views 0

Answers ( )

    0
    2021-09-04T11:39:35+00:00

    Answer:

    Explanation:

    30 N force is pulling total mass of 15 kg , so acceleration in the system of masses

    = 30 / 15

    = 2 m / s²

    Let us now consider forces acting on 9 kg . 30 N is pulling it in forward direction . Tension T in the string attached to it is pulling it in reverse direction

    so net force on it

    30 – T

    Applying Newton’s law of motion on it

    30 – T = mass x acceleration

    30 – T = 9  x 2

    30 – 18 = T

    T = 12 N

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )