tính đạo hàm hộ mình câu này với ạ….

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tính đạo hàm hộ mình câu này với ạ….
tinh-dao-ham-ho-minh-cau-nay-voi-a

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Neala 5 years 2021-05-21T03:24:26+00:00 1 Answers 20 views 0

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  1. thienan
    0
    2021-05-21T03:25:51+00:00
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    $y=\cos^6x+2\sin^4x\cos^2x-3\sin^2x\cos^4x+\sin^4x$

    $y’=6\cos^5x.(\cos x)’+2[4\sin^3x(\sin x)’\cos^2x+\sin^4x.2\cos x(\cos x)’]-3[2\sin x(\sin x)’\cos^4x+\sin^2x.4\cos^3x.(\cos x)’]+4\sin^3x(\sin x)’$

    $=-6\cos^5x\sin x+2.(4\sin^3x\cos^3x-2\cos x\sin^5x)-3(2\sin x\cos^5x-4\cos^3x.\sin^3x)+4\sin^3x\cos x$

    $=-6\cos^5x\sin x+8\sin^3x\cos^3x-4\sin^5x\cos x-6\sin x\cos^5x+12\cos^3x\sin^3x+4\sin^3x\cos x$

    $=-18\sin x\cos^5x+20\sin^3x\cos^3x-4\sin^5x\cos x+4\sin^3x\cos x$

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