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There is a right triangle with sided of lenght 33, 56 and 65. Let x be the angle opposite the side of lenght 56. A. Sin(x)= B.Co
Question
There is a right triangle with sided of lenght 33, 56 and 65. Let x be the angle opposite the side of lenght 56.
A. Sin(x)=
B.Cos(x)=
C.Sin(2x)=
D.Sin(x/2)=
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Mathematics
5 years
2021-07-31T12:26:47+00:00
2021-07-31T12:26:47+00:00 1 Answers
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Answers ( )
Answer:
sin x = 33/65, cos x = 56/65, tan x = 33/56,
sec x = 65/56, csc x = 65/33, cot x = 56/33
Step-by-step explanation:
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