Question The value of (1-w) (1 -w^2), where w is the cube root of a complex number isa) ob) 1c) 2d) 3
Answer:(1-w) (1-w*2) =1-w*2-w+w*3 =1-w-w*2+1 =1-1+1 =1 Step-by-step explanation: at first we should multiply them with each other then, put the value of w*3 i.e. w*3=1 then, put the value of -w-w*2 i.e. 1 then, the final answer is 1. Log in to Reply
Answer:(1-w) (1-w*2)
=1-w*2-w+w*3
=1-w-w*2+1
=1-1+1
=1
Step-by-step explanation:
at first we should multiply them with each other
then, put the value of w*3 i.e. w*3=1
then, put the value of -w-w*2 i.e. 1
then, the final answer is 1.