Question The value of (1-w) (1 -w^2), where w is the cube root of a complex number isa) ob) 1c) 2d) 3

Answer:(1-w) (1-w*2) =1-w*2-w+w*3 =1-w-w*2+1 =1-1+1 =1 Step-by-step explanation: at first we should multiply them with each other then, put the value of w*3 i.e. w*3=1 then, put the value of -w-w*2 i.e. 1 then, the final answer is 1. Log in to Reply

Answer:(1-w) (1-w*2)=1-w*2-w+w*3=1-w-w*2+1=1-1+1=1Step-by-step explanation:at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.