The outer dimensions of a closed rectangular cardboard box are 8 centimeters by 10 centimeters by 12 centimeters, and the six sides of the b

Question

The outer dimensions of a closed rectangular cardboard box are 8 centimeters by 10 centimeters by 12 centimeters, and the six sides of the box are uniformly 12 centimeter thick. A closed canister in the shape of a right circular cylinder is to be placed inside the box so that it stands upright when the box rests on one of its sides. Of all such canisters that would fit, what is the outer radius, in centimeters, of the canister that occupies the maximum volume

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Dâu 3 years 2021-08-02T11:32:31+00:00 1 Answers 14 views 0

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  1. Calantha
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    2021-08-02T11:34:20+00:00
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    Answer:

    Vmax = 192.33 cm³

    Step-by-step explanation: An error in the problem statement. The sides of the box could not be 12 cm. We assume 1.5 cm

    Inside dimensions of the box:

    Outer dimensions :          12          10         8

     2 *  1.5   =  3                      3            3         3

    Inside dimensions:            9            7         5

    The volume of a right circular cylinder is:

    V(c)  =  π*r²*h              r is the radius of the base and  h the height

    By simple inspection is obvious that volume maximum will occur when r is maximum, and r is maximum, only when the base of the cylinder is in the rectangle 12*10. ( Inside  dim  9*7 ) In that case r  =  7/2   r = 3.5 cm

    Then the height is 5 cm.

    And the maximum volume of the cylinder is:

    Vmax = 3.14* ( 3.5)²*5

    Vmax = 192.33 cm³

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